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X^2-2X=91
We move all terms to the left:
X^2-2X-(91)=0
a = 1; b = -2; c = -91;
Δ = b2-4ac
Δ = -22-4·1·(-91)
Δ = 368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{368}=\sqrt{16*23}=\sqrt{16}*\sqrt{23}=4\sqrt{23}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4\sqrt{23}}{2*1}=\frac{2-4\sqrt{23}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4\sqrt{23}}{2*1}=\frac{2+4\sqrt{23}}{2} $
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